90x^2+95x-5=0

Solution for 90x^2+95x-5=0 equation:

90x^2+95x-5=0

a = 90; b = 95; c = -5;
Δ = b2-4ac
Δ = 952-4·90·(-5)
Δ = 10825
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10825}=\sqrt{25*433}=\sqrt{25}*\sqrt{433}=5\sqrt{433}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(95)-5\sqrt{433}}{2*90}=\frac{-95-5\sqrt{433}}{180}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(95)+5\sqrt{433}}{2*90}=\frac{-95+5\sqrt{433}}{180}
$